Lines Matching full:var2
4175 /* Exp =Exp +len(var1) -len(var2) */
4178 /* Pad Var2 to same length as Var1 */
4179 /* msu2pair/plus=1st 2 or 1 units of var2, +1 to allow for round */
4191 /* If same then tops2=msu2pair -- {units 1&2 of var2} */
4192 var2} */
4202 /* var2=var2/10 */
4213 /* var1 is a copy of the lhs coefficient, var2 is the rhs coefficient.*/
4237 const Unit *var2; /* -> var2 array */
4238 const Unit *msu2; /* -> msu of var2 */
4441 /* subtract in place is always possible. The rhs (var2) has */
4450 /* rhs (var2) is left-aligned with var1 at the start */
4453 var2=rhs->lsu; /* -> rhs array */
4454 msu2=var2+var2units-1; /* -> msu of var2 [never changes] */
4469 /* number of leading zeros in var1 msu and subtract those in var2 msu. */
4524 if (pv2>=var2) v2=*pv2; /* in range */
4530 if (*pv1==v2) { /* var1 == var2 */
4531 /* reach here if var1 and var2 are identical; subtraction */
4538 } /* var1 == var2 */
4541 /* Bring in two units of var2 to provide a good estimate. */
4545 /* The var2 msu is one unit towards the lsu of the var1 msu, */
4546 /* so only one unit for var2 can be used. */
4550 /* subtraction needed; var1 is > var2 */
4552 /* subtract var1-var2, into var1; only the overlap needs */
4557 decDumpAr('2', var2, var2units);
4561 var2, var2units, 0,
4596 /* to get here, var1 is less than var2, so divide var2 by the per- */
4687 /* var2 residual padding, which happens to be given by: */
