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1571 \section{Root Finding}
1578 numbers (less than 1000 bits) I'd avoid $b > 3$ situations. Will return a positive root only for even roots and return
1579 a root with the sign of the input for odd roots. For example, performing $4^{1/2}$ will return $2$ whereas $(-8)^{1/3}$
1582 This algorithm uses the ``Newton Approximation'' method and will converge on the correct root fairly quickly. Since