Lines Matching refs:NaN
36 If either operand is NaN, the result is NaN.
37 The sum of two infinities of opposite sign is NaN.
46 In the remaining cases, where neither an infinity, nor a zero, nor NaN is
82 array[item++] = new TestCase( SECTION, "Number.NaN + 1", Number.NaN, Number.NaN + 1 );
83 array[item++] = new TestCase( SECTION, "1 + Number.NaN", Number.NaN, 1 + Number.NaN );
85 array[item++] = new TestCase( SECTION, "Number.NaN - 1", Number.NaN, Number.NaN - 1 );
86 array[item++] = new TestCase( SECTION, "1 - Number.NaN", Number.NaN, 1 - Number.NaN );
91 array[item++] = new TestCase( SECTION, "Number.POSITIVE_INFINITY + Number.NEGATIVE_INFINITY", Number.NaN, Number.POSITIVE_INFINITY + Number.NEGATIVE_INFINITY);
92 array[item++] = new TestCase( SECTION, "Number.NEGATIVE_INFINITY + Number.POSITIVE_INFINITY", Number.NaN, Number.NEGATIVE_INFINITY + Number.POSITIVE_INFINITY);
94 array[item++] = new TestCase( SECTION, "Number.POSITIVE_INFINITY - Number.POSITIVE_INFINITY", Number.NaN, Number.POSITIVE_INFINITY - Number.POSITIVE_INFINITY);
95 array[item++] = new TestCase( SECTION, "Number.NEGATIVE_INFINITY - Number.NEGATIVE_INFINITY", Number.NaN, Number.NEGATIVE_INFINITY - Number.NEGATIVE_INFINITY);
