Lines Matching full:assumption
3191 assumption that signed overflow does not occur. Note that it does not
3253 assumption
3328 omitted. This is done under the assumption that the zero initializer in
5428 In some environments, this assumption is not true, and programs can
6123 signed \f(CW\*(C`i\*(C'\fR. This assumption is only valid if signed overflow is
6134 \&\f(CW\*(C`u\*(C'\fR. This assumption is only valid because pointer wraparound is
14050 In order to be efficient the extra code makes the assumption that the stack starts
14793 Do output those jump instructions, on the assumption that you
