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      1 /*
      2 * The contents of this file are subject to the Netscape Public
      3 * License Version 1.1 (the "License"); you may not use this file
      4 * except in compliance with the License. You may obtain a copy of
      5 * the License at http://www.mozilla.org/NPL/
      6 *
      7 * Software distributed under the License is distributed on an "AS
      8 * IS" basis, WITHOUT WARRANTY OF ANY KIND, either express or
      9 * implied. See the License for the specific language governing
     10 * rights and limitations under the License.
     11 *
     12 * The Original Code is mozilla.org code.
     13 *
     14 * The Initial Developer of the Original Code is Netscape
     15 * Communications Corporation.  Portions created by Netscape are
     16 * Copyright (C) 1998 Netscape Communications Corporation. All
     17 * Rights Reserved.
     18 *
     19 * Contributor(s): pschwartau (at) netscape.com
     20 * Date: 26 November 2000
     21 *
     22 *
     23 *SUMMARY: Passing a RegExp object to a RegExp() constructor.
     24 *This test arose from Bugzilla bug 61266. The ECMA3 section is:
     25 *
     26 *  15.10.4.1 new RegExp(pattern, flags)
     27 *
     28 *  If pattern is an object R whose [[Class]] property is "RegExp" and
     29 *  flags is undefined, then let P be the pattern used to construct R
     30 *  and let F be the flags used to construct R. If pattern is an object R
     31 *  whose [[Class]] property is "RegExp" and flags is not undefined,
     32 *  then throw a TypeError exception. Otherwise, let P be the empty string
     33 *  if pattern is undefined and ToString(pattern) otherwise, and let F be
     34 *  the empty string if flags is undefined and ToString(flags) otherwise.
     35 *
     36 *
     37 *The current test will check the first scenario outlined above:
     38 *
     39 *   "pattern" is itself a RegExp object R
     40 *   "flags"  is undefined
     41 *
     42 * We check that a new RegExp object obj2 defined from these parameters
     43 * is morally the same as the original RegExp object obj1. Of course, they
     44 * can't be equal as objects - so we check their enumerable properties...
     45 *
     46 * In this test, the initial RegExp object obj1 will not include a flag. The flags
     47 * parameter for obj2  will be undefined in the sense of not being provided.
     48 */
     49 //-------------------------------------------------------------------------------------------------
     50 var bug = '61266';
     51 var summary = 'Passing a RegExp object to a RegExp() constructor';
     52 var statprefix = 'Applying RegExp() twice to pattern ';
     53 var statsuffix =  '; testing property ';
     54 var singlequote = "'";
     55 var i = -1; var s = '';
     56 var obj1 = {}; var obj2 = {};
     57 var status = ''; var actual = ''; var expect = ''; var msg = '';
     58 var patterns = new Array();
     59 
     60 
     61 // various regular expressions to try -
     62 patterns[0] = '';
     63 patterns[1] = 'abc';
     64 patterns[2] = '(.*)(3-1)\s\w';
     65 patterns[3] = '(.*)(...)\\s\\w';
     66 patterns[4] = '[^A-Za-z0-9_]';
     67 patterns[5] = '[^\f\n\r\t\v](123.5)([4 - 8]$)';
     68 
     69 
     70 
     71 //-------------------------------------------------------------------------------------------------
     72 test();
     73 //-------------------------------------------------------------------------------------------------
     74 
     75 
     76 function test()
     77 {
     78   enterFunc ('test');
     79   printBugNumber (bug);
     80   printStatus (summary);
     81 
     82   for (i in patterns)
     83   {
     84     s = patterns[i];
     85     status =getStatus(s);
     86     obj1 = new RegExp(s);
     87     obj2 = new RegExp(obj1);
     88 
     89     for (prop in obj2)
     90     {
     91       msg  = status +  quote(prop);
     92       actual = obj2[prop];
     93       expect = obj1[prop];
     94       reportCompare (expect, actual, msg);
     95     }
     96   }
     97 
     98   exitFunc ('test');
     99 }
    100 
    101 
    102 function getStatus(regexp)
    103 {
    104   return (statprefix  +  quote(regexp) +  statsuffix);
    105 }
    106 
    107 
    108 function quote(text)
    109 {
    110   return (singlequote  +  text  + singlequote);
    111 }