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181 	  GDate days[31];         /* This is the fast way, no allocation */
183 TEST("Sensible number of days in month", (dim > 0 && dim < 32));
189 g_date_clear(days, 31);
200 d = &days[day-1];
234 TEST("Last day of year equals number of days in year",
238 g_print("last day: %u days in year: %u\n",
243 TEST("Day of year is not more than number of days in the year",
317 /***** Days ******/
321 TEST("Adding days gives a value greater than previous",
325 TEST("Forward days then backward days returns us to current day",
334 TEST("Forward days then backward days returns us to current month",
343 TEST("Forward days then backward days returns us to current year",