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188 	  GDate days[31];         /* This is the fast way, no allocation */
190 TEST("Sensible number of days in month", (dim > 0 && dim < 32));
196 g_date_clear(days, 31);
207 d = &days[day-1];
241 TEST("Last day of year equals number of days in year",
245 g_print("last day: %u days in year: %u\n",
250 TEST("Day of year is not more than number of days in the year",
324 /***** Days ******/
328 TEST("Adding days gives a value greater than previous",
332 TEST("Forward days then backward days returns us to current day",
341 TEST("Forward days then backward days returns us to current month",
350 TEST("Forward days then backward days returns us to current year",