1 /* 2 * The contents of this file are subject to the Netscape Public 3 * License Version 1.1 (the "License"); you may not use this file 4 * except in compliance with the License. You may obtain a copy of 5 * the License at http://www.mozilla.org/NPL/ 6 * 7 * Software distributed under the License is distributed on an "AS 8 * IS" basis, WITHOUT WARRANTY OF ANY KIND, either express or 9 * implied. See the License for the specific language governing 10 * rights and limitations under the License. 11 * 12 * The Original Code is mozilla.org code. 13 * 14 * The Initial Developer of the Original Code is Netscape 15 * Communications Corporation. Portions created by Netscape are 16 * Copyright (C) 1998 Netscape Communications Corporation. All 17 * Rights Reserved. 18 * 19 * Contributor(s): pschwartau (at) netscape.com 20 * Date: 26 November 2000 21 * 22 * 23 *SUMMARY: Passing a RegExp object to a RegExp() constructor. 24 *This test arose from Bugzilla bug 61266. The ECMA3 section is: 25 * 26 * 15.10.4.1 new RegExp(pattern, flags) 27 * 28 * If pattern is an object R whose [[Class]] property is "RegExp" and 29 * flags is undefined, then let P be the pattern used to construct R 30 * and let F be the flags used to construct R. If pattern is an object R 31 * whose [[Class]] property is "RegExp" and flags is not undefined, 32 * then throw a TypeError exception. Otherwise, let P be the empty string 33 * if pattern is undefined and ToString(pattern) otherwise, and let F be 34 * the empty string if flags is undefined and ToString(flags) otherwise. 35 * 36 * 37 *The current test will check the first scenario outlined above: 38 * 39 * "pattern" is itself a RegExp object R 40 * "flags" is undefined 41 * 42 * We check that a new RegExp object obj2 defined from these parameters 43 * is morally the same as the original RegExp object obj1. Of course, they 44 * can't be equal as objects - so we check their enumerable properties... 45 * 46 * In this test, the initial RegExp object obj1 will not include a flag. This test is 47 * identical to test 15.10.4.1-1.js, except that here we use this syntax: 48 * 49 * obj2 = new RegExp(obj1, undefined); 50 * 51 * instead of: 52 * 53 * obj2 = new RegExp(obj1); 54 */ 55 //------------------------------------------------------------------------------------------------- 56 var bug = '61266'; 57 var summary = 'Passing a RegExp object to a RegExp() constructor'; 58 var statprefix = 'Applying RegExp() twice to pattern '; 59 var statsuffix = '; testing property '; 60 var singlequote = "'"; 61 var i = -1; var s = ''; 62 var obj1 = {}; var obj2 = {}; 63 var status = ''; var actual = ''; var expect = ''; var msg = ''; 64 var patterns = new Array(); 65 66 67 // various regular expressions to try - 68 patterns[0] = ''; 69 patterns[1] = 'abc'; 70 patterns[2] = '(.*)(3-1)\s\w'; 71 patterns[3] = '(.*)(...)\\s\\w'; 72 patterns[4] = '[^A-Za-z0-9_]'; 73 patterns[5] = '[^\f\n\r\t\v](123.5)([4 - 8]$)'; 74 75 76 77 //------------------------------------------------------------------------------------------------- 78 test(); 79 //------------------------------------------------------------------------------------------------- 80 81 82 function test() 83 { 84 enterFunc ('test'); 85 printBugNumber (bug); 86 printStatus (summary); 87 88 for (i in patterns) 89 { 90 s = patterns[i]; 91 status =getStatus(s); 92 obj1 = new RegExp(s); 93 obj2 = new RegExp(obj1, undefined); // see introduction to bug 94 95 for (prop in obj2) 96 { 97 msg = status + quote(prop); 98 actual = obj2[prop]; 99 expect = obj1[prop]; 100 reportCompare (expect, actual, msg); 101 } 102 } 103 104 exitFunc ('test'); 105 } 106 107 108 function getStatus(regexp) 109 { 110 return (statprefix + quote(regexp) + statsuffix); 111 } 112 113 114 function quote(text) 115 { 116 return (singlequote + text + singlequote); 117 }