Lines Matching full:reduce
1319 This will reduce $a$ in place modulo $b$ with the precomputed $\mu$ value in $c$. $a$ must be in the range
1346 /* now reduce `c' modulo b */
1360 /* now reduce `c' modulo b */
1453 /* now reduce `c' back down to c = a^2R^2 * R^-1 == a^2R */
1467 /* now reduce `c' back down to c = a^3R^2 * R^-1 == a^3R */
1474 /* now reduce (again) `c' back down to c = a^3R * R^-1 == a^3 */
1544 This will reduce $a$ in place modulo $n$ with the pre--computed value $d$. From my experience this routine is
