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Lines Matching defs:power

1658             double power = -1./b[3];
1659 fjac(i,0) = pow(1.+e, power);
1660 fjac(i,1) = power*b[0]*e*pow(1.+e, power-1.);
1661 fjac(i,2) = -power*b[0]*e*x[i]*pow(1.+e, power-1.);
1662 fjac(i,3) = b[0]*power*power*log(1.+e)*pow(1.+e, power);