Lines Matching full:used
25 /* can the fast reduction [comba] method be used?
31 digs = n->used * 2 + 1;
33 n->used <
44 x->used = digs;
46 for (ix = 0; ix < n->used; ix++) {
73 for (iy = 0; iy < n->used; iy++) {
96 /* at this point the n.used'th least
99 * right by n.used digits and the
103 /* x = x/b**n.used */
105 mp_rshd (x, n->used);
