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      1 // Copyright 2013 the V8 project authors. All rights reserved.
      2 // Copyright (C) 2005, 2006, 2007, 2008, 2009 Apple Inc. All rights reserved.
      3 //
      4 // Redistribution and use in source and binary forms, with or without
      5 // modification, are permitted provided that the following conditions
      6 // are met:
      7 // 1.  Redistributions of source code must retain the above copyright
      8 //     notice, this list of conditions and the following disclaimer.
      9 // 2.  Redistributions in binary form must reproduce the above copyright
     10 //     notice, this list of conditions and the following disclaimer in the
     11 //     documentation and/or other materials provided with the distribution.
     12 //
     13 // THIS SOFTWARE IS PROVIDED BY APPLE INC. AND ITS CONTRIBUTORS ``AS IS'' AND ANY
     14 // EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED
     15 // WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE
     16 // DISCLAIMED. IN NO EVENT SHALL APPLE INC. OR ITS CONTRIBUTORS BE LIABLE FOR ANY
     17 // DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES
     18 // (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES;
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     21 // (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF THIS
     22 // SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
     23 
     24 description(
     25 "This tests that common subexpression elimination knows how to accurately model PutBuVal."
     26 );
     27 
     28 function doAccesses(a, b, i, j, y) {
     29     var x = a[i];
     30     b[j] = y;
     31     return a[i];
     32 }
     33 
     34 var array1 = [1, 2, 3, 4];
     35 var array2 = [5, 6, 7, 8];
     36 
     37 for (var i = 0; i < 1000; ++i) {
     38     // Simple test, pretty easy to pass.
     39     shouldBe("doAccesses(array1, array2, i % 4, (i + 1) % 4, i)", "" + ((i % 4) + 1));
     40     shouldBe("array2[" + ((i + 1) % 4) + "]", "" + i);
     41 
     42     // Undo.
     43     array2[((i + 1) % 4)] = (i % 4) + 5;
     44 
     45     // Now the evil test. This is constructed to minimize the likelihood that CSE will succeed through
     46     // cleverness alone.
     47     shouldBe("doAccesses(array1, array1, i % 4, 0, i)", "" + ((i % 4) == 0 ? i : (i % 4) + 1));
     48 
     49     // Undo.
     50     array1[0] = 1;
     51 }
     52 
     53