Lines Matching full:a_1
255 .. math:: y = a_1 e^{b_1 x} + a_2 e^{b_3 x^2 + c_1}
259 :math:`a_1, a_2, b_1, b_2`, and :math:`c_1`.
261 Notice that the expression on the left is linear in :math:`a_1` and
264 of :math:`a_1` and :math:`a_2`. It's possible to analytically
265 eliminate the variables :math:`a_1` and :math:`a_2` from the problem
281 additional optimization step to estimate :math:`a_1` and :math:`a_2`
286 linear in :math:`a_1` and :math:`a_2`, i.e.,
288 .. math:: y = f_1(a_1, e^{b_1 x}) + f_2(a_2, e^{b_3 x^2 + c_1})
291 and then use it as the starting point to further optimize just `a_1`
294 the `a_1` and `a_2` optimization problems will do. The only constraint
295 on `a_1` and `a_2` (if they are two different parameter block) is that
299 :math:`(a_1, a_2)`, but decomposing the graph corresponding to the