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Lines Matching full:rsum

1935     double best_val = 0, lsum = 0, rsum = node->value*n;
1940         rsum -= responses[sorted[i].i];
1948         rsum -= t;
1952             double val = (lsum*lsum*R + rsum*rsum*L)/((double)L*R);
1979     double best_val = 0, lsum = 0, rsum = 0;
1999         rsum += sum[i];
2020             rsum -= s; R -= ni;
2024                 double val = (lsum*lsum*R + rsum*rsum*L)/((double)L*R);