Lines Matching full:fmul
2108 %mul = fmul double %conv, 0.000000e+00
2112 We should be able to fold away this fmul to 0.0. More generally, fmul(x,0.0)
2127 fmul(sitofp(x), 0.0) into 0.0, because x might be -1 and the result of the
2130 If we look at the uses of the fmul for example, we might be able to prove that
2133 fadd(fmul(sitofp(x), 0.0), 2.0)
2136 transform the fmul to 0.0, and then the fadd to 2.0.
