Lines Matching refs:glyphName
64 for glyphName in glyphNames:
68 row.append(widths[glyphName])
69 if ";" in glyphName:
70 glyphName = "\\x3b".join(glyphName.split(";"))
71 writer.write(format % ((glyphName,) + tuple(row)))
92 glyphName = line[0][:-1]
93 if "\\" in glyphName:
95 glyphName = safeEval('"""' + glyphName + '"""')
99 hdmx[ppems[i]][glyphName] = line[i]
