Lines Matching full:tdiv
31 Compute the Tdiv as the root of (cubic) equation
32 sqrt(3)/18 · |P2 - 3·C2 + 3·C1 - P1|/2 · Tdiv ^ 3 = prec
33 if Tdiv < 0.5 divide the cubic at Tdiv. First segment [0..Tdiv] can be approximated with by a
35 Repeat from step 2 with the second resulted segment (corresponding to 1-Tdiv)
36 0.5<=Tdiv<1 - simply divide the cubic in two. The two halves can be approximated by the mid-point
38 Tdiv>=1 - the entire cubic can be approximated by the mid-point approximation
91 double tDiv = calc_t_div(cubic, precision, 0);
92 if (tDiv >= 1) {
95 if (tDiv >= 0.5) {
104 double tDiv = calc_t_div(cubic, precision, 0);
105 double parts = ceil(1.0 / tDiv);
