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  /external/chromium_org/third_party/re2/re2/testing/
dump.cc 80 Rune r = re->runes()[i];
106 Rune r = re->runes()[i];
  /external/chromium_org/third_party/re2/re2/
prefilter.cc 564 info = LiteralLatin1(re->runes()[0]);
566 info = Concat(info, LiteralLatin1(re->runes()[i]));
569 info = Literal(re->runes()[0]);
571 info = Concat(info, Literal(re->runes()[i]));
regexp.h 332 Rune* runes() { DCHECK_EQ(op_, kRegexpLiteralString); return runes_; } function in class:re2::Regexp
385 // They do not consume allocated arrays like subs or runes.
395 static Regexp* LiteralString(Rune* runes, int nrunes, ParseFlags flags);
465 // Removes the first n leading runes from the beginning of re.
regexp.cc 289 Regexp* Regexp::LiteralString(Rune* runes, int nrunes, ParseFlags flags) {
293 return NewLiteral(runes[0], flags);
296 re->AddRuneToString(runes[i]);
344 memcmp(a->runes(), b->runes(),
345 a->nrunes() * sizeof a->runes()[0]) == 0;
tostring.cc 162 AppendLiteral(t_, re->runes()[i], re->parse_flags() & Regexp::FoldCase);
compile.cc 535 // the bytes that would make up those runes in the current
553 // Latin1 is easy: runes *are* bytes.
773 Frag f1 = Literal(re->runes()[i], re->parse_flags()&Regexp::FoldCase);
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