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Searched
defs:BB2
(Results
1 - 6
of
6
) sorted by null
/external/llvm/unittests/IR/
DominatorTreeTest.cpp
44
BasicBlock *
BB2
= FI++;
45
BBI =
BB2
->begin();
61
EXPECT_TRUE(DT->isReachableFromEntry(
BB2
));
68
EXPECT_TRUE(DT->dominates(BB0,
BB2
));
74
EXPECT_FALSE(DT->dominates(BB1,
BB2
));
78
EXPECT_FALSE(DT->dominates(
BB2
, BB0));
79
EXPECT_FALSE(DT->dominates(
BB2
, BB1));
80
EXPECT_TRUE(DT->dominates(
BB2
,
BB2
));
81
EXPECT_TRUE(DT->dominates(
BB2
, BB3))
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all
...]
InstructionsTest.cpp
89
BasicBlock *
BB2
= BasicBlock::Create(Ctx, "", F);
94
std::unique_ptr<InvokeInst> Invoke(InvokeInst::Create(F, BB1,
BB2
, Args));
/external/llvm/lib/Transforms/Scalar/
ConstantHoisting.cpp
249
BasicBlock *BB, *BB1, *
BB2
;
251
BB2
= *std::next(BBs.begin());
252
BB = DT->findNearestCommonDominator(BB1,
BB2
);
256
BBs.erase(
BB2
);
SampleProfile.cpp
196
/// Two blocks BB1 and
BB2
are in the same equivalence class if they
609
/// A block
BB2
will be in the same equivalence class as \p BB1 if
612
/// 1- \p BB1 is a descendant of
BB2
in the opposite tree. So, if
BB2
613
/// is a descendant of \p BB1 in the dominator tree, then
BB2
should
616
/// 2- Both
BB2
and \p BB1 must be in the same loop.
618
/// For every block
BB2
that meets those two requirements, we set
BB2
's
632
BasicBlock *
BB2
= *I;
633
bool IsDomParent = DomTree->dominates(
BB2
, BB1)
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...]
/external/clang/lib/Analysis/
ThreadSafetyCommon.cpp
736
til::BasicBlock *
BB2
= *It ? lookupBlock(*It) : nullptr;
738
unsigned Idx2 =
BB2
?
BB2
->findPredecessorIndex(CurrentBB) : 0;
739
til::SExpr *Tm = new (Arena) til::Branch(C, BB1,
BB2
, Idx1, Idx2);
/external/llvm/lib/Transforms/Utils/
SimplifyCFG.cpp
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...]
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