Home | History | Annotate | Download | only in functional

Lines Matching full:dot0

102 	int dot0 = (point.x()-p0.x()) * (p1.y()-p0.y()) + (point.y()-p0.y()) * (p0.x()-p1.x());
107 return (dot0 > 0) == (dot1 > 0) && (dot1 > 0) == (dot2 > 0) && (dot2 > 0) == (dot3 > 0);