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Searched
full:numtransforms
(Results
1 - 5
of
5
) sorted by null
/external/skia/src/gpu/glsl/
GrGLSLFragmentProcessor.cpp
73
* subtree has 3 transforms (using B.
numTransforms
()), so we know the start of D's transforms is
80
firstCoordAt += args.fFp.childProcessor(i).
numTransforms
();
85
if (childProc.
numTransforms
() > 0) {
86
childCoords.push_back_n(childProc.
numTransforms
(), &args.fCoords[firstCoordAt]);
GrGLSLGeometryProcessor.h
104
int
numTransforms
= transforms.count();
105
for (int t = 0; t <
numTransforms
; ++t) {
/external/skia/src/gpu/
GrPathProcessor.cpp
101
int
numTransforms
= transforms.count();
102
for (int t = 0; t <
numTransforms
; ++t) {
GrFragmentProcessor.cpp
35
if (this->
numTransforms
() != that.
numTransforms
()) {
119
if (this->
numTransforms
() != that.
numTransforms
()) {
122
int count = this->
numTransforms
();
/external/skia/include/gpu/
GrFragmentProcessor.h
79
int
numTransforms
() const { return fCoordTransforms.count(); }
82
numTransforms
(). */
Completed in 611 milliseconds