Home | History | Annotate | Download | only in examples

Lines Matching refs:most

208     int most;           /* most number of syms to use at this juncture */
231 /* we can use at most this many bit patterns, lest there not be enough
233 no limit to the code length, this would become: most = left - 1) */
234 most = (((code_t)left << (max - len)) - syms) /
239 for (use = least; use <= most; use++) {
325 int most; /* most number of syms to use at this juncture */
367 /* we can use at most this many bit patterns, lest there not be enough
369 no limit to the code length, this would become: most = left - 1) */
370 most = (((code_t)left << (max - len)) - syms) /
383 for (use = least; use <= most; use++) {
497 /* make sure that the calculation of most will not overflow */