Lines Matching defs:fa
43 double fa[13];50 values[i] = &fa[i];51 fa[i] = (double) i;60 ff = many(fa[0], fa[1],61 fa[2], fa[3],62 fa[4], fa[5],63 fa[6], fa[7],64 fa[8], fa[9],65 fa[10],fa[11],fa[12]);
