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46                  that the result will not saturate.
104 result = 32-bit quotient of of the division of two 32 bit integers
125 3. result = L_num * (1/L_denom).
179 Word32 result;
187 result = Mpy_32_16(L_denom_hi, L_denom_lo, approx, pOverflow);
188 /* result is > 0 , and less than 1.0 */
189 result = 0x7fffffffL - result;
191 hi = (Word16)(result >> 16);
192 lo = (result >> 1) - (hi << 15);
194 result = Mpy_32_16(hi, lo, approx, pOverflow);
198 hi = (Word16)(result >> 16);
199 lo = (result >> 1) - (hi << 15);
204 result = Mpy_32(n_hi, n_lo, hi, lo, pOverflow);
205 result = L_shl(result, 2, pOverflow);
207 return (result);