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217      * will be the number of floats remaining in this buffer, and its mark
341 * destination array. If there are fewer floats remaining in the
343 * <tt>length</tt>&nbsp;<tt>&gt;</tt>&nbsp;<tt>remaining()</tt>, then no
381 * remaining in this buffer
389 if (length > remaining())
414 * remaining in this buffer
426 * <p> This method transfers the floats remaining in the given source
427 * buffer into this buffer. If there are more floats remaining in the
429 * <tt>src.remaining()</tt>&nbsp;<tt>&gt;</tt>&nbsp;<tt>remaining()</tt>,
434 * <i>n</i>&nbsp;=&nbsp;<tt>src.remaining()</tt> floats from the given
456 * for the remaining floats in the source buffer
467 int n = src.remaining();
468 if (n > remaining())
481 * <tt>length</tt>&nbsp;<tt>&gt;</tt>&nbsp;<tt>remaining()</tt>, then no
528 if (length > remaining())
692 * <p> The hash code of a float buffer depends only upon its remaining
719 * <li><p> They have the same number of remaining elements, and
722 * <li><p> The two sequences of remaining elements, considered
748 if (this.remaining() != that.remaining())
768 * remaining elements lexicographically, without regard to the starting
788 int n = this.position() + Math.min(this.remaining(), that.remaining());
794 return this.remaining() - that.remaining();