Lines Matching defs:last
151 * int end = boundary.last();
172 * Print last element:
176 * int end = boundary.last();
200 * int last = wb.following(pos);
203 * for (int p = last; p < current; p++) {
205 * return last;
207 * last = current;
256 * and following(int) when either the first or last text boundary has been
269 * Returns the last boundary. The iterator's current position is set
270 * to the last text boundary.
271 * @return The character index of the last text boundary.
273 public abstract int last();
277 * the first or last text boundary has been reached, it returns
279 * the first or last text boundary depending on which one is reached. Otherwise,
282 * and three more boundaries exist from the current boundary to the last text
285 * <code>BreakIterator.DONE</code> and the last text boundary would become the
291 * or <code>BreakIterator.DONE</code> if either first or last text boundary
298 * is the last text boundary, it returns <code>BreakIterator.DONE</code> and
302 * <code>BreakIterator.DONE</code> if the current boundary is the last text
322 * specified offset equals to the last text boundary, it returns
329 * <code>BreakIterator.DONE</code> if the last text boundary is passed in
332 * the first text boundary or greater than the last text boundary.
337 * Returns the last boundary preceding the specified character offset. If the
344 * @return The last boundary before the specified offset or
348 * the first text boundary or greater than the last text boundary.
368 * the first text boundary or greater than the last text boundary.
392 * recently returned by next(), next(int), previous(), first(), last(),
394 * <code>BreakIterator.DONE</code> because either first or last text boundary
395 * has been reached, it returns the first or last text boundary depending on
397 * @return The text boundary returned from the above methods, first or last
403 * @see #last()
