Lines Matching defs:log1p
22 // double log1p(double x)
36 // 2. Approximation of log1p(f).
54 // log1p(f) = f - (hfsq - s*(hfsq+R)).
56 // 3. Finally, log1p(x) = k*ln2 + log1p(f).
63 // log1p(x) is NaN with signal if x < -1 (including -INF) ;
64 // log1p(+INF) is +INF; log1p(-1) is -INF with signal;
65 // log1p(NaN) is that NaN with no signal.
78 // algorithm can be used to compute log1p(x) to within a few ULP:
86 // Log1p returns the natural logarithm of 1 plus its argument x.
90 // Log1p(+Inf) = +Inf
91 // Log1p(±0) = ±0
92 // Log1p(-1) = -Inf
93 // Log1p(x < -1) = NaN
94 // Log1p(NaN) = NaN
95 func Log1p(x float64) float64
97 func log1p(x float64) float64 {
