1 """ 2 Broken bytecode objects can easily crash the interpreter. 3 4 This is not going to be fixed. It is generally agreed that there is no 5 point in writing a bytecode verifier and putting it in CPython just for 6 this. Moreover, a verifier is bound to accept only a subset of all safe 7 bytecodes, so it could lead to unnecessary breakage. 8 9 For security purposes, "restricted" interpreters are not going to let 10 the user build or load random bytecodes anyway. Otherwise, this is a 11 "won't fix" case. 12 13 """ 14 15 import types 16 17 co = types.CodeType(0, 0, 0, 0, 0, b'\x04\x71\x00\x00', 18 (), (), (), '', '', 1, b'') 19 exec(co) 20
