1 #!/usr/bin/env python 2 # Copyright (c) 2009, Google Inc. All rights reserved. 3 # Copyright (c) 2009 Apple Inc. All rights reserved. 4 # 5 # Redistribution and use in source and binary forms, with or without 6 # modification, are permitted provided that the following conditions are 7 # met: 8 # 9 # * Redistributions of source code must retain the above copyright 10 # notice, this list of conditions and the following disclaimer. 11 # * Redistributions in binary form must reproduce the above 12 # copyright notice, this list of conditions and the following disclaimer 13 # in the documentation and/or other materials provided with the 14 # distribution. 15 # * Neither the name of Google Inc. nor the names of its 16 # contributors may be used to endorse or promote products derived from 17 # this software without specific prior written permission. 18 # 19 # THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS 20 # "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT 21 # LIMITED TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR 22 # A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT 23 # OWNER OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, 24 # SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT 25 # LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, 26 # DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY 27 # THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT 28 # (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE 29 # OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE. 30 31 import re 32 33 34 def plural(noun): 35 # This is a dumb plural() implementation that is just enough for our uses. 36 if re.search("h$", noun): 37 return noun + "es" 38 else: 39 return noun + "s" 40 41 42 def pluralize(noun, count): 43 if count != 1: 44 noun = plural(noun) 45 return "%d %s" % (count, noun) 46 47 48 def join_with_separators(list_of_strings, separator=', ', last_separator=', and '): 49 if not list_of_strings: 50 return "" 51 if len(list_of_strings) == 1: 52 return list_of_strings[0] 53 return "%s%s%s" % (separator.join(list_of_strings[:-1]), last_separator, list_of_strings[-1]) 54
