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      1 
      2 /* @(#)e_atanh.c 1.3 95/01/18 */
      3 /*
      4  * ====================================================
      5  * Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved.
      6  *
      7  * Developed at SunSoft, a Sun Microsystems, Inc. business.
      8  * Permission to use, copy, modify, and distribute this
      9  * software is freely granted, provided that this notice
     10  * is preserved.
     11  * ====================================================
     12  *
     13  */
     14 
     15 #ifndef lint
     16 static char rcsid[] = "$FreeBSD: src/lib/msun/src/e_atanh.c,v 1.7 2005/02/04 18:26:05 das Exp $";
     17 #endif
     18 
     19 /* __ieee754_atanh(x)
     20  * Method :
     21  *    1.Reduced x to positive by atanh(-x) = -atanh(x)
     22  *    2.For x>=0.5
     23  *                  1              2x                          x
     24  *	atanh(x) = --- * log(1 + -------) = 0.5 * log1p(2 * --------)
     25  *                  2             1 - x                      1 - x
     26  *
     27  * 	For x<0.5
     28  *	atanh(x) = 0.5*log1p(2x+2x*x/(1-x))
     29  *
     30  * Special cases:
     31  *	atanh(x) is NaN if |x| > 1 with signal;
     32  *	atanh(NaN) is that NaN with no signal;
     33  *	atanh(+-1) is +-INF with signal.
     34  *
     35  */
     36 
     37 #include "math.h"
     38 #include "math_private.h"
     39 
     40 static const double one = 1.0, huge = 1e300;
     41 static const double zero = 0.0;
     42 
     43 double
     44 __ieee754_atanh(double x)
     45 {
     46 	double t;
     47 	int32_t hx,ix;
     48 	u_int32_t lx;
     49 	EXTRACT_WORDS(hx,lx,x);
     50 	ix = hx&0x7fffffff;
     51 	if ((ix|((lx|(-lx))>>31))>0x3ff00000) /* |x|>1 */
     52 	    return (x-x)/(x-x);
     53 	if(ix==0x3ff00000)
     54 	    return x/zero;
     55 	if(ix<0x3e300000&&(huge+x)>zero) return x;	/* x<2**-28 */
     56 	SET_HIGH_WORD(x,ix);
     57 	if(ix<0x3fe00000) {		/* x < 0.5 */
     58 	    t = x+x;
     59 	    t = 0.5*log1p(t+t*x/(one-x));
     60 	} else
     61 	    t = 0.5*log1p((x+x)/(one-x));
     62 	if(hx>=0) return t; else return -t;
     63 }
     64