1 /* 2 * Copyright (C) 2012 The Android Open Source Project 3 * 4 * Licensed under the Apache License, Version 2.0 (the "License"); 5 * you may not use this file except in compliance with the License. 6 * You may obtain a copy of the License at 7 * 8 * http://www.apache.org/licenses/LICENSE-2.0 9 * 10 * Unless required by applicable law or agreed to in writing, software 11 * distributed under the License is distributed on an "AS IS" BASIS, 12 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. 13 * See the License for the specific language governing permissions and 14 * limitations under the License. 15 */ 16 17 package com.android.uiautomator.tree; 18 19 import java.util.ArrayList; 20 import java.util.Collections; 21 import java.util.List; 22 23 public class BasicTreeNode { 24 25 private static final BasicTreeNode[] CHILDREN_TEMPLATE = new BasicTreeNode[] {}; 26 27 protected BasicTreeNode mParent; 28 29 protected final List<BasicTreeNode> mChildren = new ArrayList<BasicTreeNode>(); 30 31 public int x, y, width, height; 32 33 // whether the boundary fields are applicable for the node or not 34 // RootWindowNode has no bounds, but UiNodes should 35 protected boolean mHasBounds = false; 36 37 public void addChild(BasicTreeNode child) { 38 if (child == null) { 39 throw new NullPointerException("Cannot add null child"); 40 } 41 if (mChildren.contains(child)) { 42 throw new IllegalArgumentException("node already a child"); 43 } 44 mChildren.add(child); 45 child.mParent = this; 46 } 47 48 public List<BasicTreeNode> getChildrenList() { 49 return Collections.unmodifiableList(mChildren); 50 } 51 52 public BasicTreeNode[] getChildren() { 53 return mChildren.toArray(CHILDREN_TEMPLATE); 54 } 55 56 public BasicTreeNode getParent() { 57 return mParent; 58 } 59 60 public boolean hasChild() { 61 return mChildren.size() != 0; 62 } 63 64 public int getChildCount() { 65 return mChildren.size(); 66 } 67 68 public void clearAllChildren() { 69 for (BasicTreeNode child : mChildren) { 70 child.clearAllChildren(); 71 } 72 mChildren.clear(); 73 } 74 75 /** 76 * 77 * Find nodes in the tree containing the coordinate 78 * 79 * The found node should have bounds covering the coordinate, and none of its children's 80 * bounds covers it. Depending on the layout, some app may have multiple nodes matching it, 81 * the caller must provide a {@link IFindNodeListener} to receive all found nodes 82 * 83 * @param px 84 * @param py 85 * @return 86 */ 87 public boolean findLeafMostNodesAtPoint(int px, int py, IFindNodeListener listener) { 88 boolean foundInChild = false; 89 for (BasicTreeNode node : mChildren) { 90 foundInChild |= node.findLeafMostNodesAtPoint(px, py, listener); 91 } 92 // checked all children, if at least one child covers the point, return directly 93 if (foundInChild) return true; 94 // check self if the node has no children, or no child nodes covers the point 95 if (mHasBounds) { 96 if (x <= px && px <= x + width && y <= py && py <= y + height) { 97 listener.onFoundNode(this); 98 return true; 99 } else { 100 return false; 101 } 102 } else { 103 return false; 104 } 105 } 106 107 public Object[] getAttributesArray () { 108 return null; 109 }; 110 111 public static interface IFindNodeListener { 112 void onFoundNode(BasicTreeNode node); 113 } 114 } 115