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      1 /*
      2  * Copyright (C) 2012 The Android Open Source Project
      3  *
      4  * Licensed under the Apache License, Version 2.0 (the "License");
      5  * you may not use this file except in compliance with the License.
      6  * You may obtain a copy of the License at
      7  *
      8  *      http://www.apache.org/licenses/LICENSE-2.0
      9  *
     10  * Unless required by applicable law or agreed to in writing, software
     11  * distributed under the License is distributed on an "AS IS" BASIS,
     12  * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
     13  * See the License for the specific language governing permissions and
     14  * limitations under the License.
     15  */
     16 
     17 package com.android.inputmethod.latin.utils;
     18 
     19 import com.android.inputmethod.annotations.UsedForTesting;
     20 import com.android.inputmethod.latin.Constants;
     21 import com.android.inputmethod.latin.settings.SettingsValues;
     22 
     23 import android.text.TextUtils;
     24 import android.util.JsonReader;
     25 import android.util.JsonWriter;
     26 import android.util.Log;
     27 
     28 import java.io.IOException;
     29 import java.io.StringReader;
     30 import java.io.StringWriter;
     31 import java.util.ArrayList;
     32 import java.util.Collections;
     33 import java.util.List;
     34 import java.util.Locale;
     35 
     36 public final class StringUtils {
     37     private static final String TAG = StringUtils.class.getSimpleName();
     38     public static final int CAPITALIZE_NONE = 0;  // No caps, or mixed case
     39     public static final int CAPITALIZE_FIRST = 1; // First only
     40     public static final int CAPITALIZE_ALL = 2;   // All caps
     41 
     42     private StringUtils() {
     43         // This utility class is not publicly instantiable.
     44     }
     45 
     46     public static int codePointCount(final String text) {
     47         if (TextUtils.isEmpty(text)) return 0;
     48         return text.codePointCount(0, text.length());
     49     }
     50 
     51     public static String newSingleCodePointString(int codePoint) {
     52         if (Character.charCount(codePoint) == 1) {
     53             // Optimization: avoid creating an temporary array for characters that are
     54             // represented by a single char value
     55             return String.valueOf((char) codePoint);
     56         }
     57         // For surrogate pair
     58         return new String(Character.toChars(codePoint));
     59     }
     60 
     61     public static boolean containsInArray(final String text, final String[] array) {
     62         for (final String element : array) {
     63             if (text.equals(element)) return true;
     64         }
     65         return false;
     66     }
     67 
     68     /**
     69      * Comma-Splittable Text is similar to Comma-Separated Values (CSV) but has much simpler syntax.
     70      * Unlike CSV, Comma-Splittable Text has no escaping mechanism, so that the text can't contain
     71      * a comma character in it.
     72      */
     73     private static final String SEPARATOR_FOR_COMMA_SPLITTABLE_TEXT = ",";
     74 
     75     public static boolean containsInCommaSplittableText(final String text,
     76             final String extraValues) {
     77         if (TextUtils.isEmpty(extraValues)) {
     78             return false;
     79         }
     80         return containsInArray(text, extraValues.split(SEPARATOR_FOR_COMMA_SPLITTABLE_TEXT));
     81     }
     82 
     83     public static String appendToCommaSplittableTextIfNotExists(final String text,
     84             final String extraValues) {
     85         if (TextUtils.isEmpty(extraValues)) {
     86             return text;
     87         }
     88         if (containsInCommaSplittableText(text, extraValues)) {
     89             return extraValues;
     90         }
     91         return extraValues + SEPARATOR_FOR_COMMA_SPLITTABLE_TEXT + text;
     92     }
     93 
     94     public static String removeFromCommaSplittableTextIfExists(final String text,
     95             final String extraValues) {
     96         if (TextUtils.isEmpty(extraValues)) {
     97             return "";
     98         }
     99         final String[] elements = extraValues.split(SEPARATOR_FOR_COMMA_SPLITTABLE_TEXT);
    100         if (!containsInArray(text, elements)) {
    101             return extraValues;
    102         }
    103         final ArrayList<String> result = CollectionUtils.newArrayList(elements.length - 1);
    104         for (final String element : elements) {
    105             if (!text.equals(element)) {
    106                 result.add(element);
    107             }
    108         }
    109         return TextUtils.join(SEPARATOR_FOR_COMMA_SPLITTABLE_TEXT, result);
    110     }
    111 
    112     /**
    113      * Remove duplicates from an array of strings.
    114      *
    115      * This method will always keep the first occurrence of all strings at their position
    116      * in the array, removing the subsequent ones.
    117      */
    118     public static void removeDupes(final ArrayList<String> suggestions) {
    119         if (suggestions.size() < 2) return;
    120         int i = 1;
    121         // Don't cache suggestions.size(), since we may be removing items
    122         while (i < suggestions.size()) {
    123             final String cur = suggestions.get(i);
    124             // Compare each suggestion with each previous suggestion
    125             for (int j = 0; j < i; j++) {
    126                 final String previous = suggestions.get(j);
    127                 if (TextUtils.equals(cur, previous)) {
    128                     suggestions.remove(i);
    129                     i--;
    130                     break;
    131                 }
    132             }
    133             i++;
    134         }
    135     }
    136 
    137     public static String capitalizeFirstCodePoint(final String s, final Locale locale) {
    138         if (s.length() <= 1) {
    139             return s.toUpperCase(locale);
    140         }
    141         // Please refer to the comment below in
    142         // {@link #capitalizeFirstAndDowncaseRest(String,Locale)} as this has the same shortcomings
    143         final int cutoff = s.offsetByCodePoints(0, 1);
    144         return s.substring(0, cutoff).toUpperCase(locale) + s.substring(cutoff);
    145     }
    146 
    147     public static String capitalizeFirstAndDowncaseRest(final String s, final Locale locale) {
    148         if (s.length() <= 1) {
    149             return s.toUpperCase(locale);
    150         }
    151         // TODO: fix the bugs below
    152         // - This does not work for Greek, because it returns upper case instead of title case.
    153         // - It does not work for Serbian, because it fails to account for the "lj" character,
    154         // which should be "Lj" in title case and "LJ" in upper case.
    155         // - It does not work for Dutch, because it fails to account for the "ij" digraph when it's
    156         // written as two separate code points. They are two different characters but both should
    157         // be capitalized as "IJ" as if they were a single letter in most words (not all). If the
    158         // unicode char for the ligature is used however, it works.
    159         final int cutoff = s.offsetByCodePoints(0, 1);
    160         return s.substring(0, cutoff).toUpperCase(locale) + s.substring(cutoff).toLowerCase(locale);
    161     }
    162 
    163     private static final int[] EMPTY_CODEPOINTS = {};
    164 
    165     public static int[] toCodePointArray(final String string) {
    166         final int length = string.length();
    167         if (length <= 0) {
    168             return EMPTY_CODEPOINTS;
    169         }
    170         final int[] codePoints = new int[string.codePointCount(0, length)];
    171         int destIndex = 0;
    172         for (int index = 0; index < length; index = string.offsetByCodePoints(index, 1)) {
    173             codePoints[destIndex] = string.codePointAt(index);
    174             destIndex++;
    175         }
    176         return codePoints;
    177     }
    178 
    179     // This method assumes the text is not null. For the empty string, it returns CAPITALIZE_NONE.
    180     public static int getCapitalizationType(final String text) {
    181         // If the first char is not uppercase, then the word is either all lower case or
    182         // camel case, and in either case we return CAPITALIZE_NONE.
    183         final int len = text.length();
    184         int index = 0;
    185         for (; index < len; index = text.offsetByCodePoints(index, 1)) {
    186             if (Character.isLetter(text.codePointAt(index))) {
    187                 break;
    188             }
    189         }
    190         if (index == len) return CAPITALIZE_NONE;
    191         if (!Character.isUpperCase(text.codePointAt(index))) {
    192             return CAPITALIZE_NONE;
    193         }
    194         int capsCount = 1;
    195         int letterCount = 1;
    196         for (index = text.offsetByCodePoints(index, 1); index < len;
    197                 index = text.offsetByCodePoints(index, 1)) {
    198             if (1 != capsCount && letterCount != capsCount) break;
    199             final int codePoint = text.codePointAt(index);
    200             if (Character.isUpperCase(codePoint)) {
    201                 ++capsCount;
    202                 ++letterCount;
    203             } else if (Character.isLetter(codePoint)) {
    204                 // We need to discount non-letters since they may not be upper-case, but may
    205                 // still be part of a word (e.g. single quote or dash, as in "IT'S" or "FULL-TIME")
    206                 ++letterCount;
    207             }
    208         }
    209         // We know the first char is upper case. So we want to test if either every letter other
    210         // than the first is lower case, or if they are all upper case. If the string is exactly
    211         // one char long, then we will arrive here with letterCount 1, and this is correct, too.
    212         if (1 == capsCount) return CAPITALIZE_FIRST;
    213         return (letterCount == capsCount ? CAPITALIZE_ALL : CAPITALIZE_NONE);
    214     }
    215 
    216     public static boolean isIdenticalAfterUpcase(final String text) {
    217         final int length = text.length();
    218         int i = 0;
    219         while (i < length) {
    220             final int codePoint = text.codePointAt(i);
    221             if (Character.isLetter(codePoint) && !Character.isUpperCase(codePoint)) {
    222                 return false;
    223             }
    224             i += Character.charCount(codePoint);
    225         }
    226         return true;
    227     }
    228 
    229     public static boolean isIdenticalAfterDowncase(final String text) {
    230         final int length = text.length();
    231         int i = 0;
    232         while (i < length) {
    233             final int codePoint = text.codePointAt(i);
    234             if (Character.isLetter(codePoint) && !Character.isLowerCase(codePoint)) {
    235                 return false;
    236             }
    237             i += Character.charCount(codePoint);
    238         }
    239         return true;
    240     }
    241 
    242     @UsedForTesting
    243     public static boolean looksValidForDictionaryInsertion(final CharSequence text,
    244             final SettingsValues settings) {
    245         if (TextUtils.isEmpty(text)) return false;
    246         final int length = text.length();
    247         int i = 0;
    248         int digitCount = 0;
    249         while (i < length) {
    250             final int codePoint = Character.codePointAt(text, i);
    251             final int charCount = Character.charCount(codePoint);
    252             i += charCount;
    253             if (Character.isDigit(codePoint)) {
    254                 // Count digits: see below
    255                 digitCount += charCount;
    256                 continue;
    257             }
    258             if (!settings.isWordCodePoint(codePoint)) return false;
    259         }
    260         // We reject strings entirely comprised of digits to avoid using PIN codes or credit
    261         // card numbers. It would come in handy for word prediction though; a good example is
    262         // when writing one's address where the street number is usually quite discriminative,
    263         // as well as the postal code.
    264         return digitCount < length;
    265     }
    266 
    267     public static boolean isIdenticalAfterCapitalizeEachWord(final String text,
    268             final String separators) {
    269         boolean needCapsNext = true;
    270         final int len = text.length();
    271         for (int i = 0; i < len; i = text.offsetByCodePoints(i, 1)) {
    272             final int codePoint = text.codePointAt(i);
    273             if (Character.isLetter(codePoint)) {
    274                 if ((needCapsNext && !Character.isUpperCase(codePoint))
    275                         || (!needCapsNext && !Character.isLowerCase(codePoint))) {
    276                     return false;
    277                 }
    278             }
    279             // We need a capital letter next if this is a separator.
    280             needCapsNext = (-1 != separators.indexOf(codePoint));
    281         }
    282         return true;
    283     }
    284 
    285     // TODO: like capitalizeFirst*, this does not work perfectly for Dutch because of the IJ digraph
    286     // which should be capitalized together in *some* cases.
    287     public static String capitalizeEachWord(final String text, final String separators,
    288             final Locale locale) {
    289         final StringBuilder builder = new StringBuilder();
    290         boolean needCapsNext = true;
    291         final int len = text.length();
    292         for (int i = 0; i < len; i = text.offsetByCodePoints(i, 1)) {
    293             final String nextChar = text.substring(i, text.offsetByCodePoints(i, 1));
    294             if (needCapsNext) {
    295                 builder.append(nextChar.toUpperCase(locale));
    296             } else {
    297                 builder.append(nextChar.toLowerCase(locale));
    298             }
    299             // We need a capital letter next if this is a separator.
    300             needCapsNext = (-1 != separators.indexOf(nextChar.codePointAt(0)));
    301         }
    302         return builder.toString();
    303     }
    304 
    305     /**
    306      * Approximates whether the text before the cursor looks like a URL.
    307      *
    308      * This is not foolproof, but it should work well in the practice.
    309      * Essentially it walks backward from the cursor until it finds something that's not a letter,
    310      * digit, or common URL symbol like underscore. If it hasn't found a period yet, then it
    311      * does not look like a URL.
    312      * If the text:
    313      * - starts with www and contains a period
    314      * - starts with a slash preceded by either a slash, whitespace, or start-of-string
    315      * Then it looks like a URL and we return true. Otherwise, we return false.
    316      *
    317      * Note: this method is called quite often, and should be fast.
    318      *
    319      * TODO: This will return that "abc./def" and ".abc/def" look like URLs to keep down the
    320      * code complexity, but ideally it should not. It's acceptable for now.
    321      */
    322     public static boolean lastPartLooksLikeURL(final CharSequence text) {
    323         int i = text.length();
    324         if (0 == i) return false;
    325         int wCount = 0;
    326         int slashCount = 0;
    327         boolean hasSlash = false;
    328         boolean hasPeriod = false;
    329         int codePoint = 0;
    330         while (i > 0) {
    331             codePoint =  Character.codePointBefore(text, i);
    332             if (codePoint < Constants.CODE_PERIOD || codePoint > 'z') {
    333                 // Handwavy heuristic to see if that's a URL character. Anything between period
    334                 // and z. This includes all lower- and upper-case ascii letters, period,
    335                 // underscore, arrobase, question mark, equal sign. It excludes spaces, exclamation
    336                 // marks, double quotes...
    337                 // Anything that's not a URL-like character causes us to break from here and
    338                 // evaluate normally.
    339                 break;
    340             }
    341             if (Constants.CODE_PERIOD == codePoint) {
    342                 hasPeriod = true;
    343             }
    344             if (Constants.CODE_SLASH == codePoint) {
    345                 hasSlash = true;
    346                 if (2 == ++slashCount) {
    347                     return true;
    348                 }
    349             } else {
    350                 slashCount = 0;
    351             }
    352             if ('w' == codePoint) {
    353                 ++wCount;
    354             } else {
    355                 wCount = 0;
    356             }
    357             i = Character.offsetByCodePoints(text, i, -1);
    358         }
    359         // End of the text run.
    360         // If it starts with www and includes a period, then it looks like a URL.
    361         if (wCount >= 3 && hasPeriod) return true;
    362         // If it starts with a slash, and the code point before is whitespace, it looks like an URL.
    363         if (1 == slashCount && (0 == i || Character.isWhitespace(codePoint))) return true;
    364         // If it has both a period and a slash, it looks like an URL.
    365         if (hasPeriod && hasSlash) return true;
    366         // Otherwise, it doesn't look like an URL.
    367         return false;
    368     }
    369 
    370     public static boolean isEmptyStringOrWhiteSpaces(String s) {
    371         final int N = codePointCount(s);
    372         for (int i = 0; i < N; ++i) {
    373             if (!Character.isWhitespace(s.codePointAt(i))) {
    374                 return false;
    375             }
    376         }
    377         return true;
    378     }
    379 
    380     @UsedForTesting
    381     public static String byteArrayToHexString(byte[] bytes) {
    382         if (bytes == null || bytes.length == 0) {
    383             return "";
    384         }
    385         final StringBuilder sb = new StringBuilder();
    386         for (byte b : bytes) {
    387             sb.append(String.format("%02x", b & 0xff));
    388         }
    389         return sb.toString();
    390     }
    391 
    392     /**
    393      * Convert hex string to byte array. The string length must be an even number.
    394      */
    395     @UsedForTesting
    396     public static byte[] hexStringToByteArray(String hexString) {
    397         if (TextUtils.isEmpty(hexString)) {
    398             return null;
    399         }
    400         final int N = hexString.length();
    401         if (N % 2 != 0) {
    402             throw new NumberFormatException("Input hex string length must be an even number."
    403                     + " Length = " + N);
    404         }
    405         final byte[] bytes = new byte[N / 2];
    406         for (int i = 0; i < N; i += 2) {
    407             bytes[i / 2] = (byte) ((Character.digit(hexString.charAt(i), 16) << 4)
    408                     + Character.digit(hexString.charAt(i + 1), 16));
    409         }
    410         return bytes;
    411     }
    412 
    413     public static List<Object> jsonStrToList(String s) {
    414         final ArrayList<Object> retval = CollectionUtils.newArrayList();
    415         final JsonReader reader = new JsonReader(new StringReader(s));
    416         try {
    417             reader.beginArray();
    418             while(reader.hasNext()) {
    419                 reader.beginObject();
    420                 while (reader.hasNext()) {
    421                     final String name = reader.nextName();
    422                     if (name.equals(Integer.class.getSimpleName())) {
    423                         retval.add(reader.nextInt());
    424                     } else if (name.equals(String.class.getSimpleName())) {
    425                         retval.add(reader.nextString());
    426                     } else {
    427                         Log.w(TAG, "Invalid name: " + name);
    428                         reader.skipValue();
    429                     }
    430                 }
    431                 reader.endObject();
    432             }
    433             reader.endArray();
    434             return retval;
    435         } catch (IOException e) {
    436         } finally {
    437             try {
    438                 reader.close();
    439             } catch (IOException e) {
    440             }
    441         }
    442         return Collections.<Object>emptyList();
    443     }
    444 
    445     public static String listToJsonStr(List<Object> list) {
    446         if (list == null || list.isEmpty()) {
    447             return "";
    448         }
    449         final StringWriter sw = new StringWriter();
    450         final JsonWriter writer = new JsonWriter(sw);
    451         try {
    452             writer.beginArray();
    453             for (final Object o : list) {
    454                 writer.beginObject();
    455                 if (o instanceof Integer) {
    456                     writer.name(Integer.class.getSimpleName()).value((Integer)o);
    457                 } else if (o instanceof String) {
    458                     writer.name(String.class.getSimpleName()).value((String)o);
    459                 }
    460                 writer.endObject();
    461             }
    462             writer.endArray();
    463             return sw.toString();
    464         } catch (IOException e) {
    465         } finally {
    466             try {
    467                 if (writer != null) {
    468                     writer.close();
    469                 }
    470             } catch (IOException e) {
    471             }
    472         }
    473         return "";
    474     }
    475 }
    476