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      1 // Ceres Solver - A fast non-linear least squares minimizer
      2 // Copyright 2010, 2011, 2012 Google Inc. All rights reserved.
      3 // http://code.google.com/p/ceres-solver/
      4 //
      5 // Redistribution and use in source and binary forms, with or without
      6 // modification, are permitted provided that the following conditions are met:
      7 //
      8 // * Redistributions of source code must retain the above copyright notice,
      9 //   this list of conditions and the following disclaimer.
     10 // * Redistributions in binary form must reproduce the above copyright notice,
     11 //   this list of conditions and the following disclaimer in the documentation
     12 //   and/or other materials provided with the distribution.
     13 // * Neither the name of Google Inc. nor the names of its contributors may be
     14 //   used to endorse or promote products derived from this software without
     15 //   specific prior written permission.
     16 //
     17 // THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS "AS IS"
     18 // AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
     19 // IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
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     24 // INTERRUPTION) HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN
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     27 // POSSIBILITY OF SUCH DAMAGE.
     28 //
     29 // Author: keir (at) google.com (Keir Mierle)
     30 //
     31 // Minimize 0.5 (10 - x)^2 using jacobian matrix computed using
     32 // numeric differentiation.
     33 
     34 #include "ceres/ceres.h"
     35 #include "glog/logging.h"
     36 
     37 using ceres::NumericDiffCostFunction;
     38 using ceres::CENTRAL;
     39 using ceres::CostFunction;
     40 using ceres::Problem;
     41 using ceres::Solver;
     42 using ceres::Solve;
     43 
     44 // A cost functor that implements the residual r = 10 - x.
     45 struct CostFunctor {
     46   bool operator()(const double* const x, double* residual) const {
     47     residual[0] = 10.0 - x[0];
     48     return true;
     49   }
     50 };
     51 
     52 int main(int argc, char** argv) {
     53   google::InitGoogleLogging(argv[0]);
     54 
     55   // The variable to solve for with its initial value. It will be
     56   // mutated in place by the solver.
     57   double x = 0.5;
     58   const double initial_x = x;
     59 
     60   // Build the problem.
     61   Problem problem;
     62 
     63   // Set up the only cost function (also known as residual). This uses
     64   // numeric differentiation to obtain the derivative (jacobian).
     65   CostFunction* cost_function =
     66       new NumericDiffCostFunction<CostFunctor, CENTRAL, 1, 1> (new CostFunctor);
     67   problem.AddResidualBlock(cost_function, NULL, &x);
     68 
     69   // Run the solver!
     70   Solver::Options options;
     71   options.minimizer_progress_to_stdout = true;
     72   Solver::Summary summary;
     73   Solve(options, &problem, &summary);
     74 
     75   std::cout << summary.BriefReport() << "\n";
     76   std::cout << "x : " << initial_x
     77             << " -> " << x << "\n";
     78   return 0;
     79 }
     80