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      1 ; RUN: opt < %s -loop-reduce -S | grep phi | count 1
      2 
      3 ; This testcase should have ONE stride 18 indvar, the other use should have a
      4 ; loop invariant value (B) added to it inside of the loop, instead of having
      5 ; a whole indvar based on B for it.
      6 
      7 declare i1 @cond(i32)
      8 
      9 define void @test(i32 %B) {
     10 ; <label>:0
     11 	br label %Loop
     12 Loop:		; preds = %Loop, %0
     13 	%IV = phi i32 [ 0, %0 ], [ %IVn, %Loop ]		; <i32> [#uses=3]
     14 	%C = mul i32 %IV, 18		; <i32> [#uses=1]
     15 	%D = mul i32 %IV, 18		; <i32> [#uses=1]
     16 	%E = add i32 %D, %B		; <i32> [#uses=1]
     17 	%cnd = call i1 @cond( i32 %E )		; <i1> [#uses=1]
     18 	call i1 @cond( i32 %C )		; <i1>:1 [#uses=0]
     19 	%IVn = add i32 %IV, 1		; <i32> [#uses=1]
     20 	br i1 %cnd, label %Loop, label %Out
     21 Out:		; preds = %Loop
     22 	ret void
     23 }
     24 
     25