1 /* 2 * Copyright (C) 2013 The Android Open Source Project 3 * All rights reserved. 4 * 5 * Redistribution and use in source and binary forms, with or without 6 * modification, are permitted provided that the following conditions 7 * are met: 8 * * Redistributions of source code must retain the above copyright 9 * notice, this list of conditions and the following disclaimer. 10 * * Redistributions in binary form must reproduce the above copyright 11 * notice, this list of conditions and the following disclaimer in 12 * the documentation and/or other materials provided with the 13 * distribution. 14 * 15 * THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS 16 * "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT 17 * LIMITED TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS 18 * FOR A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE 19 * COPYRIGHT OWNER OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, 20 * INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, 21 * BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS 22 * OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED 23 * AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, 24 * OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT 25 * OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF 26 * SUCH DAMAGE. 27 */ 28 29 // Contains an implementation of all stdlib functions missing from bionic. 30 // 31 // TODO(digit): Make these work. 32 33 #include <inttypes.h> 34 #include <stdlib.h> 35 #include <assert.h> 36 37 long double strtold(const char* nptr, char** endptr) { 38 //FIXME: Although in Android long double is the same as double, can we borrow stdtod? 39 return strtod(nptr, endptr); 40 } 41 42 intmax_t imaxabs(intmax_t j) 43 { 44 return (j < 0 ? -j : j); 45 } 46 47 imaxdiv_t imaxdiv(intmax_t numer, intmax_t denom) 48 { 49 imaxdiv_t retval; 50 51 retval.quot = numer / denom; 52 retval.rem = numer % denom; 53 if (numer >= 0 && retval.rem < 0) { 54 retval.quot++; 55 retval.rem -= denom; 56 } 57 return (retval); 58 } 59
