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      1 extern int g1, g2;
      2 extern void foo(int n);
      3 
      4 int main() {
      5   int i, j;
      6   for (i = 0; i < 1000; i++)
      7     for (j = 0; j < 1000; j++)
      8       foo(i * j);
      9 
     10   if (g2 - g1 == 280001)
     11     return 0;
     12   return 1;
     13 }
     14