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      1 // Copyright 2010 The Go Authors. All rights reserved.
      2 // Use of this source code is governed by a BSD-style
      3 // license that can be found in the LICENSE file.
      4 
      5 package math
      6 
      7 // The original C code, the long comment, and the constants
      8 // below are from FreeBSD's /usr/src/lib/msun/src/s_expm1.c
      9 // and came with this notice. The go code is a simplified
     10 // version of the original C.
     11 //
     12 // ====================================================
     13 // Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved.
     14 //
     15 // Developed at SunPro, a Sun Microsystems, Inc. business.
     16 // Permission to use, copy, modify, and distribute this
     17 // software is freely granted, provided that this notice
     18 // is preserved.
     19 // ====================================================
     20 //
     21 // expm1(x)
     22 // Returns exp(x)-1, the exponential of x minus 1.
     23 //
     24 // Method
     25 //   1. Argument reduction:
     26 //      Given x, find r and integer k such that
     27 //
     28 //               x = k*ln2 + r,  |r| <= 0.5*ln2 ~ 0.34658
     29 //
     30 //      Here a correction term c will be computed to compensate
     31 //      the error in r when rounded to a floating-point number.
     32 //
     33 //   2. Approximating expm1(r) by a special rational function on
     34 //      the interval [0,0.34658]:
     35 //      Since
     36 //          r*(exp(r)+1)/(exp(r)-1) = 2+ r**2/6 - r**4/360 + ...
     37 //      we define R1(r*r) by
     38 //          r*(exp(r)+1)/(exp(r)-1) = 2+ r**2/6 * R1(r*r)
     39 //      That is,
     40 //          R1(r**2) = 6/r *((exp(r)+1)/(exp(r)-1) - 2/r)
     41 //                   = 6/r * ( 1 + 2.0*(1/(exp(r)-1) - 1/r))
     42 //                   = 1 - r**2/60 + r**4/2520 - r**6/100800 + ...
     43 //      We use a special Reme algorithm on [0,0.347] to generate
     44 //      a polynomial of degree 5 in r*r to approximate R1. The
     45 //      maximum error of this polynomial approximation is bounded
     46 //      by 2**-61. In other words,
     47 //          R1(z) ~ 1.0 + Q1*z + Q2*z**2 + Q3*z**3 + Q4*z**4 + Q5*z**5
     48 //      where   Q1  =  -1.6666666666666567384E-2,
     49 //              Q2  =   3.9682539681370365873E-4,
     50 //              Q3  =  -9.9206344733435987357E-6,
     51 //              Q4  =   2.5051361420808517002E-7,
     52 //              Q5  =  -6.2843505682382617102E-9;
     53 //      (where z=r*r, and the values of Q1 to Q5 are listed below)
     54 //      with error bounded by
     55 //          |                  5           |     -61
     56 //          | 1.0+Q1*z+...+Q5*z   -  R1(z) | <= 2
     57 //          |                              |
     58 //
     59 //      expm1(r) = exp(r)-1 is then computed by the following
     60 //      specific way which minimize the accumulation rounding error:
     61 //                             2     3
     62 //                            r     r    [ 3 - (R1 + R1*r/2)  ]
     63 //            expm1(r) = r + --- + --- * [--------------------]
     64 //                            2     2    [ 6 - r*(3 - R1*r/2) ]
     65 //
     66 //      To compensate the error in the argument reduction, we use
     67 //              expm1(r+c) = expm1(r) + c + expm1(r)*c
     68 //                         ~ expm1(r) + c + r*c
     69 //      Thus c+r*c will be added in as the correction terms for
     70 //      expm1(r+c). Now rearrange the term to avoid optimization
     71 //      screw up:
     72 //                      (      2                                    2 )
     73 //                      ({  ( r    [ R1 -  (3 - R1*r/2) ]  )  }    r  )
     74 //       expm1(r+c)~r - ({r*(--- * [--------------------]-c)-c} - --- )
     75 //                      ({  ( 2    [ 6 - r*(3 - R1*r/2) ]  )  }    2  )
     76 //                      (                                             )
     77 //
     78 //                 = r - E
     79 //   3. Scale back to obtain expm1(x):
     80 //      From step 1, we have
     81 //         expm1(x) = either 2**k*[expm1(r)+1] - 1
     82 //                  = or     2**k*[expm1(r) + (1-2**-k)]
     83 //   4. Implementation notes:
     84 //      (A). To save one multiplication, we scale the coefficient Qi
     85 //           to Qi*2**i, and replace z by (x**2)/2.
     86 //      (B). To achieve maximum accuracy, we compute expm1(x) by
     87 //        (i)   if x < -56*ln2, return -1.0, (raise inexact if x!=inf)
     88 //        (ii)  if k=0, return r-E
     89 //        (iii) if k=-1, return 0.5*(r-E)-0.5
     90 //        (iv)  if k=1 if r < -0.25, return 2*((r+0.5)- E)
     91 //                     else          return  1.0+2.0*(r-E);
     92 //        (v)   if (k<-2||k>56) return 2**k(1-(E-r)) - 1 (or exp(x)-1)
     93 //        (vi)  if k <= 20, return 2**k((1-2**-k)-(E-r)), else
     94 //        (vii) return 2**k(1-((E+2**-k)-r))
     95 //
     96 // Special cases:
     97 //      expm1(INF) is INF, expm1(NaN) is NaN;
     98 //      expm1(-INF) is -1, and
     99 //      for finite argument, only expm1(0)=0 is exact.
    100 //
    101 // Accuracy:
    102 //      according to an error analysis, the error is always less than
    103 //      1 ulp (unit in the last place).
    104 //
    105 // Misc. info.
    106 //      For IEEE double
    107 //          if x >  7.09782712893383973096e+02 then expm1(x) overflow
    108 //
    109 // Constants:
    110 // The hexadecimal values are the intended ones for the following
    111 // constants. The decimal values may be used, provided that the
    112 // compiler will convert from decimal to binary accurately enough
    113 // to produce the hexadecimal values shown.
    114 //
    115 
    116 // Expm1 returns e**x - 1, the base-e exponential of x minus 1.
    117 // It is more accurate than Exp(x) - 1 when x is near zero.
    118 //
    119 // Special cases are:
    120 //	Expm1(+Inf) = +Inf
    121 //	Expm1(-Inf) = -1
    122 //	Expm1(NaN) = NaN
    123 // Very large values overflow to -1 or +Inf.
    124 func Expm1(x float64) float64
    125 
    126 func expm1(x float64) float64 {
    127 	const (
    128 		Othreshold = 7.09782712893383973096e+02 // 0x40862E42FEFA39EF
    129 		Ln2X56     = 3.88162421113569373274e+01 // 0x4043687a9f1af2b1
    130 		Ln2HalfX3  = 1.03972077083991796413e+00 // 0x3ff0a2b23f3bab73
    131 		Ln2Half    = 3.46573590279972654709e-01 // 0x3fd62e42fefa39ef
    132 		Ln2Hi      = 6.93147180369123816490e-01 // 0x3fe62e42fee00000
    133 		Ln2Lo      = 1.90821492927058770002e-10 // 0x3dea39ef35793c76
    134 		InvLn2     = 1.44269504088896338700e+00 // 0x3ff71547652b82fe
    135 		Tiny       = 1.0 / (1 << 54)            // 2**-54 = 0x3c90000000000000
    136 		// scaled coefficients related to expm1
    137 		Q1 = -3.33333333333331316428e-02 // 0xBFA11111111110F4
    138 		Q2 = 1.58730158725481460165e-03  // 0x3F5A01A019FE5585
    139 		Q3 = -7.93650757867487942473e-05 // 0xBF14CE199EAADBB7
    140 		Q4 = 4.00821782732936239552e-06  // 0x3ED0CFCA86E65239
    141 		Q5 = -2.01099218183624371326e-07 // 0xBE8AFDB76E09C32D
    142 	)
    143 
    144 	// special cases
    145 	switch {
    146 	case IsInf(x, 1) || IsNaN(x):
    147 		return x
    148 	case IsInf(x, -1):
    149 		return -1
    150 	}
    151 
    152 	absx := x
    153 	sign := false
    154 	if x < 0 {
    155 		absx = -absx
    156 		sign = true
    157 	}
    158 
    159 	// filter out huge argument
    160 	if absx >= Ln2X56 { // if |x| >= 56 * ln2
    161 		if sign {
    162 			return -1 // x < -56*ln2, return -1
    163 		}
    164 		if absx >= Othreshold { // if |x| >= 709.78...
    165 			return Inf(1)
    166 		}
    167 	}
    168 
    169 	// argument reduction
    170 	var c float64
    171 	var k int
    172 	if absx > Ln2Half { // if  |x| > 0.5 * ln2
    173 		var hi, lo float64
    174 		if absx < Ln2HalfX3 { // and |x| < 1.5 * ln2
    175 			if !sign {
    176 				hi = x - Ln2Hi
    177 				lo = Ln2Lo
    178 				k = 1
    179 			} else {
    180 				hi = x + Ln2Hi
    181 				lo = -Ln2Lo
    182 				k = -1
    183 			}
    184 		} else {
    185 			if !sign {
    186 				k = int(InvLn2*x + 0.5)
    187 			} else {
    188 				k = int(InvLn2*x - 0.5)
    189 			}
    190 			t := float64(k)
    191 			hi = x - t*Ln2Hi // t * Ln2Hi is exact here
    192 			lo = t * Ln2Lo
    193 		}
    194 		x = hi - lo
    195 		c = (hi - x) - lo
    196 	} else if absx < Tiny { // when |x| < 2**-54, return x
    197 		return x
    198 	} else {
    199 		k = 0
    200 	}
    201 
    202 	// x is now in primary range
    203 	hfx := 0.5 * x
    204 	hxs := x * hfx
    205 	r1 := 1 + hxs*(Q1+hxs*(Q2+hxs*(Q3+hxs*(Q4+hxs*Q5))))
    206 	t := 3 - r1*hfx
    207 	e := hxs * ((r1 - t) / (6.0 - x*t))
    208 	if k == 0 {
    209 		return x - (x*e - hxs) // c is 0
    210 	}
    211 	e = (x*(e-c) - c)
    212 	e -= hxs
    213 	switch {
    214 	case k == -1:
    215 		return 0.5*(x-e) - 0.5
    216 	case k == 1:
    217 		if x < -0.25 {
    218 			return -2 * (e - (x + 0.5))
    219 		}
    220 		return 1 + 2*(x-e)
    221 	case k <= -2 || k > 56: // suffice to return exp(x)-1
    222 		y := 1 - (e - x)
    223 		y = Float64frombits(Float64bits(y) + uint64(k)<<52) // add k to y's exponent
    224 		return y - 1
    225 	}
    226 	if k < 20 {
    227 		t := Float64frombits(0x3ff0000000000000 - (0x20000000000000 >> uint(k))) // t=1-2**-k
    228 		y := t - (e - x)
    229 		y = Float64frombits(Float64bits(y) + uint64(k)<<52) // add k to y's exponent
    230 		return y
    231 	}
    232 	t = Float64frombits(uint64(0x3ff-k) << 52) // 2**-k
    233 	y := x - (e + t)
    234 	y++
    235 	y = Float64frombits(Float64bits(y) + uint64(k)<<52) // add k to y's exponent
    236 	return y
    237 }
    238